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bug 776789 FK in another db

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This commit is contained in:
Marc Delisle 2003-07-25 12:11:54 +00:00
parent 5f397a7fbb
commit bfac313494
3 changed files with 15 additions and 7 deletions
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2
ChangeLog
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@ -7,6 +7,8 @@ $Source$
2003-07-25 Marc Delisle <lem9@users.sourceforge.net>
* header.inc.php3: XHTML compatibility
* libraries/sqlparser.lib.php3, /relation.lib.php3: bug 776789,
unable to insert record with FK in another db
2003-07-24 Garvin Hicking <me@supergarv.de>
* libraries/sqlparser.lib.php3 - Confirmation is also needed on

10
libraries/relation.lib.php3
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@ -311,21 +311,21 @@ if (!defined('PMA_RELATION_LIB_INCLUDED')){
$show_create_table_res = PMA_mysql_query($show_create_table_query);
list(,$show_create_table) = PMA_mysql_fetch_row($show_create_table_res);
$analyzed_sql = PMA_SQP_analyze(PMA_SQP_parse($show_create_table));
while (list(,$one_key) = each ($analyzed_sql[0]['foreign_keys'])) {
// the analyzer may return more than one column name in the
// index list or the ref_index_list
while (list($i,$field) = each($one_key['index_list'])) {
// TODO: SHOW CREATE TABLE does not return the db name in
// the REFERENCES, so we assume the same db as master
// If a foreign key is defined in the 'internal' source (pmadb)
// and in 'innodb', we won't get it twice if $source='both'
// because we use $field as key
$foreign[$field]['foreign_db'] = $db;
if (isset($one_key['ref_db_name'])) {
$foreign[$field]['foreign_db'] = $one_key['ref_db_name'];
} else {
$foreign[$field]['foreign_db'] = $db;
}
$foreign[$field]['foreign_table'] = $one_key['ref_table_name'];
$foreign[$field]['foreign_field'] = $one_key['ref_index_list'][$i];
}

10
libraries/sqlparser.lib.php3
View File

@ -1394,7 +1394,6 @@ if (!defined('PMA_SQP_LIB_INCLUDED')) {
if ($seen_foreign && $in_bracket) {
// remove backquotes
$identifier = str_replace('`','',$arr[$i]['data']);
//$foreign_key_number++;
$foreign[$foreign_key_number]['index_list'][] = $identifier;
}
@ -1403,7 +1402,14 @@ if (!defined('PMA_SQP_LIB_INCLUDED')) {
if ($in_bracket) {
$foreign[$foreign_key_number]['ref_index_list'][] = $identifier;
} else {
$foreign[$foreign_key_number]['ref_table_name'] = $identifier;
// identifier can be table or db.table
$db_table = explode('.',$identifier);
if (isset($db_table[1])) {
$foreign[$foreign_key_number]['ref_db_name'] = $db_table[0];
$foreign[$foreign_key_number]['ref_table_name'] = $db_table[1];
} else {
$foreign[$foreign_key_number]['ref_table_name'] = $db_table[0];
}
}
}
}