Fix php error when using strlen on null
Signed-off-by: William Desportes <williamdes@wdes.fr>
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@ -2420,7 +2420,7 @@ class InsertEdit
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$foreigner['foreign_table']
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);
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// Field to display from the foreign table?
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if ($display_field !== null && strlen($display_field) > 0) {
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if (is_string($display_field) && strlen($display_field) > 0) {
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$dispsql = 'SELECT ' . Util::backquote($display_field)
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. ' FROM ' . Util::backquote($foreigner['foreign_db'])
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. '.' . Util::backquote($foreigner['foreign_table'])
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